Base | Representation |
---|---|
bin | 11001000001000001001110… |
… | …100010110011110010100011 |
3 | 112102112220221121002110221011 |
4 | 121001001032202303302203 |
5 | 103410041404200032321 |
6 | 1025555012545241351 |
7 | 32113524620541301 |
oct | 3101011642636243 |
9 | 472486847073834 |
10 | 110021200002211 |
11 | 32068802177683 |
12 | 1040aa19333257 |
13 | 4950c54471574 |
14 | 1d250a9757271 |
15 | cabd859b9ae1 |
hex | 64104e8b3ca3 |
110021200002211 has 2 divisors, whose sum is σ = 110021200002212. Its totient is φ = 110021200002210.
The previous prime is 110021200002179. The next prime is 110021200002229. The reversal of 110021200002211 is 112200002120011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110021200002211 - 25 = 110021200002179 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 110021200002191 and 110021200002200.
It is not a weakly prime, because it can be changed into another prime (110021200042211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010600001105 + 55010600001106.
It is an arithmetic number, because the mean of its divisors is an integer number (55010600001106).
Almost surely, 2110021200002211 is an apocalyptic number.
110021200002211 is a deficient number, since it is larger than the sum of its proper divisors (1).
110021200002211 is an equidigital number, since it uses as much as digits as its factorization.
110021200002211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 110021200002211 its reverse (112200002120011), we get a palindrome (222221202122222).
The spelling of 110021200002211 in words is "one hundred ten trillion, twenty-one billion, two hundred million, two thousand, two hundred eleven".
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