Base | Representation |
---|---|
bin | 10000000000101001110… |
… | …000001011000001100011 |
3 | 10220011211200012122222222 |
4 | 100000221300023001203 |
5 | 121011213300343244 |
6 | 2201232552021255 |
7 | 142326165506105 |
oct | 20005160130143 |
9 | 3804750178888 |
10 | 1100212121699 |
11 | 394663073189 |
12 | 15928a99182b |
13 | 7c998a17a82 |
14 | 3b371723575 |
15 | 1d944401bee |
hex | 10029c0b063 |
1100212121699 has 2 divisors, whose sum is σ = 1100212121700. Its totient is φ = 1100212121698.
The previous prime is 1100212121689. The next prime is 1100212121719. The reversal of 1100212121699 is 9961212120011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100212121699 - 232 = 1095917154403 is a prime.
It is a super-3 number, since 3×11002121216993 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1100212121689) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550106060849 + 550106060850.
It is an arithmetic number, because the mean of its divisors is an integer number (550106060850).
Almost surely, 21100212121699 is an apocalyptic number.
1100212121699 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100212121699 is an equidigital number, since it uses as much as digits as its factorization.
1100212121699 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 35.
The spelling of 1100212121699 in words is "one trillion, one hundred billion, two hundred twelve million, one hundred twenty-one thousand, six hundred ninety-nine".
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