Base | Representation |
---|---|
bin | 11001000001000001001111… |
… | …101111001001011101101101 |
3 | 112102112220222222202011212001 |
4 | 121001001033233021131231 |
5 | 103410041424310421213 |
6 | 1025555014542212301 |
7 | 32113525252616434 |
oct | 3101011757113555 |
9 | 472486888664761 |
10 | 110021220013933 |
11 | 320688124a5798 |
12 | 1040aa23b84091 |
13 | 4950c5865a117 |
14 | 1d250ac28611b |
15 | cabd8761e1dd |
hex | 64104fbc976d |
110021220013933 has 2 divisors, whose sum is σ = 110021220013934. Its totient is φ = 110021220013932.
The previous prime is 110021220013847. The next prime is 110021220013949. The reversal of 110021220013933 is 339310022120011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 66802718463849 + 43218501550084 = 8173293^2 + 6574078^2 .
It is a cyclic number.
It is not a de Polignac number, because 110021220013933 - 245 = 74836847925101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110021220013963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010610006966 + 55010610006967.
It is an arithmetic number, because the mean of its divisors is an integer number (55010610006967).
Almost surely, 2110021220013933 is an apocalyptic number.
It is an amenable number.
110021220013933 is a deficient number, since it is larger than the sum of its proper divisors (1).
110021220013933 is an equidigital number, since it uses as much as digits as its factorization.
110021220013933 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 28.
Adding to 110021220013933 its reverse (339310022120011), we get a palindrome (449331242133944).
The spelling of 110021220013933 in words is "one hundred ten trillion, twenty-one billion, two hundred twenty million, thirteen thousand, nine hundred thirty-three".
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