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110021220013933 is a prime number
BaseRepresentation
bin11001000001000001001111…
…101111001001011101101101
3112102112220222222202011212001
4121001001033233021131231
5103410041424310421213
61025555014542212301
732113525252616434
oct3101011757113555
9472486888664761
10110021220013933
11320688124a5798
121040aa23b84091
134950c5865a117
141d250ac28611b
15cabd8761e1dd
hex64104fbc976d

110021220013933 has 2 divisors, whose sum is σ = 110021220013934. Its totient is φ = 110021220013932.

The previous prime is 110021220013847. The next prime is 110021220013949. The reversal of 110021220013933 is 339310022120011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66802718463849 + 43218501550084 = 8173293^2 + 6574078^2 .

It is a cyclic number.

It is not a de Polignac number, because 110021220013933 - 245 = 74836847925101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110021220013963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010610006966 + 55010610006967.

It is an arithmetic number, because the mean of its divisors is an integer number (55010610006967).

Almost surely, 2110021220013933 is an apocalyptic number.

It is an amenable number.

110021220013933 is a deficient number, since it is larger than the sum of its proper divisors (1).

110021220013933 is an equidigital number, since it uses as much as digits as its factorization.

110021220013933 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 28.

Adding to 110021220013933 its reverse (339310022120011), we get a palindrome (449331242133944).

The spelling of 110021220013933 in words is "one hundred ten trillion, twenty-one billion, two hundred twenty million, thirteen thousand, nine hundred thirty-three".