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1100213201203 = 9511115677973
BaseRepresentation
bin10000000000101001110…
…100010010100100110011
310220011211202020111210121
4100000221310102210303
5121011214034414303
62201233031111111
7142326210623254
oct20005164224463
93804752214717
101100213201203
11394663740236
1215928b212497
137c99900522c
143b371924b2b
151d9445669bd
hex10029d12933

1100213201203 has 4 divisors (see below), whose sum is σ = 1100328888688. Its totient is φ = 1100097513720.

The previous prime is 1100213201177. The next prime is 1100213201239. The reversal of 1100213201203 is 3021023120011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1100213201203 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1100213201803) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57829476 + ... + 57848497.

It is an arithmetic number, because the mean of its divisors is an integer number (275082222172).

Almost surely, 21100213201203 is an apocalyptic number.

1100213201203 is a deficient number, since it is larger than the sum of its proper divisors (115687485).

1100213201203 is an equidigital number, since it uses as much as digits as its factorization.

1100213201203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 115687484.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1100213201203 its reverse (3021023120011), we get a palindrome (4121236321214).

The spelling of 1100213201203 in words is "one trillion, one hundred billion, two hundred thirteen million, two hundred one thousand, two hundred three".

Divisors: 1 9511 115677973 1100213201203