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110021423 is a prime number
BaseRepresentation
bin1101000111011…
…00101100101111
321200000200000112
412203230230233
5211131141143
614530050235
72504111111
oct643545457
9250020015
10110021423
11571167a6
1230a1997b
1319a42045
141087d3b1
1599d3e18
hex68ecb2f

110021423 has 2 divisors, whose sum is σ = 110021424. Its totient is φ = 110021422.

The previous prime is 110021413. The next prime is 110021453. The reversal of 110021423 is 324120011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 110021423 - 214 = 110005039 is a prime.

It is a super-3 number, since 3×1100214233 (a number of 25 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110021398 and 110021407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110021413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010711 + 55010712.

It is an arithmetic number, because the mean of its divisors is an integer number (55010712).

Almost surely, 2110021423 is an apocalyptic number.

110021423 is a deficient number, since it is larger than the sum of its proper divisors (1).

110021423 is an equidigital number, since it uses as much as digits as its factorization.

110021423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 110021423 is about 10489.1097334331. The cubic root of 110021423 is about 479.1730887138.

Adding to 110021423 its reverse (324120011), we get a palindrome (434141434).

The spelling of 110021423 in words is "one hundred ten million, twenty-one thousand, four hundred twenty-three".