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11002142411 = 1343172311423
BaseRepresentation
bin10100011111100011…
…10101111011001011
31001101202110202001222
422033301311323023
5140013022024121
65015422032255
7536433444641
oct121761657313
931352422058
1011002142411
114736471487
12217071868b
1310644c7850
147652ab191
15445d640ab
hex28fc75ecb

11002142411 has 16 divisors (see below), whose sum is σ = 12132105216. Its totient is φ = 9913016736.

The previous prime is 11002142407. The next prime is 11002142419. The reversal of 11002142411 is 11424120011.

It is a cyclic number.

It is not a de Polignac number, because 11002142411 - 22 = 11002142407 is a prime.

It is a super-3 number, since 3×110021424113 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11002142411.

It is not an unprimeable number, because it can be changed into a prime (11002142419) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 957446 + ... + 968868.

It is an arithmetic number, because the mean of its divisors is an integer number (758256576).

Almost surely, 211002142411 is an apocalyptic number.

11002142411 is a deficient number, since it is larger than the sum of its proper divisors (1129962805).

11002142411 is a wasteful number, since it uses less digits than its factorization.

11002142411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13202.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 11002142411 its reverse (11424120011), we get a palindrome (22426262422).

The spelling of 11002142411 in words is "eleven billion, two million, one hundred forty-two thousand, four hundred eleven".

Divisors: 1 13 43 559 1723 11423 22399 74089 148499 491189 963157 6385457 19681829 255863777 846318647 11002142411