Base | Representation |
---|---|
bin | 110011001110111010… |
… | …0101000000101001011 |
3 | 101111222121210202000212 |
4 | 1212131310220011023 |
5 | 3300311113012341 |
6 | 122313213151335 |
7 | 10643306402141 |
oct | 1463564500513 |
9 | 344877722025 |
10 | 110022000971 |
11 | 42729607833 |
12 | 193a618b54b |
13 | a4b4c3102c |
14 | 547a0ad591 |
15 | 2cddee15eb |
hex | 199dd2814b |
110022000971 has 2 divisors, whose sum is σ = 110022000972. Its totient is φ = 110022000970.
The previous prime is 110022000931. The next prime is 110022001009. The reversal of 110022000971 is 179000220011.
It is a strong prime.
It is an emirp because it is prime and its reverse (179000220011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110022000971 - 210 = 110021999947 is a prime.
It is not a weakly prime, because it can be changed into another prime (110022000901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55011000485 + 55011000486.
It is an arithmetic number, because the mean of its divisors is an integer number (55011000486).
Almost surely, 2110022000971 is an apocalyptic number.
110022000971 is a deficient number, since it is larger than the sum of its proper divisors (1).
110022000971 is an equidigital number, since it uses as much as digits as its factorization.
110022000971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 23.
Adding to 110022000971 its reverse (179000220011), we get a palindrome (289022220982).
The spelling of 110022000971 in words is "one hundred ten billion, twenty-two million, nine hundred seventy-one", and thus it is an aban number.
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