11002200112121 has 4 divisors (see below), whose sum is σ = 11002266735744. Its totient is φ = 11002133488500.

The previous prime is 11002200112103. The next prime is 11002200112139. The reversal of 11002200112121 is 12121100220011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (11002200112103) and next prime (11002200112139).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11002200112121 is a prime.

It is a super-2 number, since 2×11002200112121² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11002200112096 and 11002200112105.

It is not an unprimeable number, because it can be changed into a prime (11002200142121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33063485 + ... + 33394586.

It is an arithmetic number, because the mean of its divisors is an integer number (2750566683936).

Almost surely, 2^{11002200112121} is an apocalyptic number.

It is an amenable number.

11002200112121 is a deficient number, since it is larger than the sum of its proper divisors (66623623).

11002200112121 is an equidigital number, since it uses as much as digits as its factorization.

11002200112121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66623622.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 11002200112121 its reverse (12121100220011), we get a palindrome (23123300332132).

The spelling of 11002200112121 in words is "eleven trillion, two billion, two hundred million, one hundred twelve thousand, one hundred twenty-one".