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11002202221141 is a prime number
BaseRepresentation
bin1010000000011010011001…
…0110101110101001010101
31102221210121101112002210101
42200012212112232221111
52420230002232034031
635222201504454101
72213611553563165
oct240064626565125
942853541462711
1011002202221141
11356200a36628a
12129837331a331
1361a6707526a1
142a071bc305a5
151412d4bb4361
hexa01a65aea55

11002202221141 has 2 divisors, whose sum is σ = 11002202221142. Its totient is φ = 11002202221140.

The previous prime is 11002202221091. The next prime is 11002202221189. The reversal of 11002202221141 is 14112220220011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9928460694916 + 1073741526225 = 3150946^2 + 1036215^2 .

It is a cyclic number.

It is not a de Polignac number, because 11002202221141 - 27 = 11002202221013 is a prime.

It is a super-3 number, since 3×110022022211413 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11002202221741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501101110570 + 5501101110571.

It is an arithmetic number, because the mean of its divisors is an integer number (5501101110571).

Almost surely, 211002202221141 is an apocalyptic number.

It is an amenable number.

11002202221141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11002202221141 is an equidigital number, since it uses as much as digits as its factorization.

11002202221141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 19.

Adding to 11002202221141 its reverse (14112220220011), we get a palindrome (25114422441152).

The spelling of 11002202221141 in words is "eleven trillion, two billion, two hundred two million, two hundred twenty-one thousand, one hundred forty-one".