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110022100120957 is a prime number
BaseRepresentation
bin11001000001000010000100…
…001100011111010101111101
3112102120000021022211020201111
4121001002010030133111331
5103410100230112332312
61025555242142042021
732113556130453223
oct3101020414372575
9472500238736644
10110022100120957
1132069124280172
121040b02a879311
134951068aa9ccb
141d25153104b13
15cabdd9a1b8a7
hex64108431f57d

110022100120957 has 2 divisors, whose sum is σ = 110022100120958. Its totient is φ = 110022100120956.

The previous prime is 110022100120913. The next prime is 110022100120973. The reversal of 110022100120957 is 759021001220011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109032461143321 + 989638977636 = 10441861^2 + 994806^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110022100120957 is a prime.

It is a super-3 number, since 3×1100221001209573 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110022100160957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55011050060478 + 55011050060479.

It is an arithmetic number, because the mean of its divisors is an integer number (55011050060479).

Almost surely, 2110022100120957 is an apocalyptic number.

It is an amenable number.

110022100120957 is a deficient number, since it is larger than the sum of its proper divisors (1).

110022100120957 is an equidigital number, since it uses as much as digits as its factorization.

110022100120957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520, while the sum is 31.

Adding to 110022100120957 its reverse (759021001220011), we get a palindrome (869043101340968).

The spelling of 110022100120957 in words is "one hundred ten trillion, twenty-two billion, one hundred million, one hundred twenty thousand, nine hundred fifty-seven".