Base | Representation |
---|---|
bin | 10100011111100100… |
… | …00110011011110001 |
3 | 1001101202121011211111 |
4 | 22033302012123301 |
5 | 140013031210113 |
6 | 5015423313321 |
7 | 536434146043 |
oct | 121762063361 |
9 | 31352534744 |
10 | 11002210033 |
11 | 4736508271 |
12 | 217074b841 |
13 | 106451c569 |
14 | 7652c7a93 |
15 | 445d7913d |
hex | 28fc866f1 |
11002210033 has 2 divisors, whose sum is σ = 11002210034. Its totient is φ = 11002210032.
The previous prime is 11002210027. The next prime is 11002210081. The reversal of 11002210033 is 33001220011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8762270449 + 2239939584 = 93607^2 + 47328^2 .
It is a cyclic number.
It is not a de Polignac number, because 11002210033 - 225 = 10968655601 is a prime.
It is a super-2 number, since 2×110022100332 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11002209995 and 11002210022.
It is not a weakly prime, because it can be changed into another prime (11002210003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501105016 + 5501105017.
It is an arithmetic number, because the mean of its divisors is an integer number (5501105017).
Almost surely, 211002210033 is an apocalyptic number.
It is an amenable number.
11002210033 is a deficient number, since it is larger than the sum of its proper divisors (1).
11002210033 is an equidigital number, since it uses as much as digits as its factorization.
11002210033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 11002210033 its reverse (33001220011), we get a palindrome (44003430044).
The spelling of 11002210033 in words is "eleven billion, two million, two hundred ten thousand, thirty-three".
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