Base | Representation |
---|---|
bin | 11001000001000010000101… |
… | …011100001011001110000011 |
3 | 112102120000022210010112011122 |
4 | 121001002011130023032003 |
5 | 103410100300434310201 |
6 | 1025555244205502455 |
7 | 32113556503144325 |
oct | 3101020534131603 |
9 | 472500283115148 |
10 | 110022121010051 |
11 | 32069135048488 |
12 | 1040b035871a2b |
13 | 4951070212013 |
14 | 1d25155bc1615 |
15 | cabddb795e1b |
hex | 64108570b383 |
110022121010051 has 2 divisors, whose sum is σ = 110022121010052. Its totient is φ = 110022121010050.
The previous prime is 110022121010029. The next prime is 110022121010069. The reversal of 110022121010051 is 150010121220011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110022121010051 - 218 = 110022120747907 is a prime.
It is a super-2 number, since 2×1100221210100512 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110022121010251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55011060505025 + 55011060505026.
It is an arithmetic number, because the mean of its divisors is an integer number (55011060505026).
Almost surely, 2110022121010051 is an apocalyptic number.
110022121010051 is a deficient number, since it is larger than the sum of its proper divisors (1).
110022121010051 is an equidigital number, since it uses as much as digits as its factorization.
110022121010051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 110022121010051 its reverse (150010121220011), we get a palindrome (260032242230062).
The spelling of 110022121010051 in words is "one hundred ten trillion, twenty-two billion, one hundred twenty-one million, ten thousand, fifty-one".
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