Base | Representation |
---|---|
bin | 110011001110111010… |
… | …1011101100110110100 |
3 | 101111222122012212202220 |
4 | 1212131311131212310 |
5 | 3300311142021322 |
6 | 122313222002340 |
7 | 10643311304262 |
oct | 1463565354664 |
9 | 344878185686 |
10 | 110022220212 |
11 | 42729747523 |
12 | 193a62763b0 |
13 | a4b4ca9a68 |
14 | 547a129432 |
15 | 2cde03655c |
hex | 199dd5d9b4 |
110022220212 has 48 divisors (see below), whose sum is σ = 262749527040. Its totient is φ = 35812895328.
The previous prime is 110022220207. The next prime is 110022220279. The reversal of 110022220212 is 212022220011.
It is a junction number, because it is equal to n+sod(n) for n = 110022220191 and 110022220200.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2445739 + ... + 2490317.
It is an arithmetic number, because the mean of its divisors is an integer number (5473948480).
Almost surely, 2110022220212 is an apocalyptic number.
110022220212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
110022220212 is an abundant number, since it is smaller than the sum of its proper divisors (152727306828).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
110022220212 is a wasteful number, since it uses less digits than its factorization.
110022220212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49412 (or 49410 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 15.
Adding to 110022220212 its reverse (212022220011), we get a palindrome (322044440223).
The spelling of 110022220212 in words is "one hundred ten billion, twenty-two million, two hundred twenty thousand, two hundred twelve".
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