Base | Representation |
---|---|
bin | 1010000000011010011110… |
… | …0110001000010010011001 |
3 | 1102221210122211200120210020 |
4 | 2200012213212020102121 |
5 | 2420230023044114140 |
6 | 35222203530541053 |
7 | 2213612225523450 |
oct | 240064746102231 |
9 | 42853584616706 |
10 | 11002223035545 |
11 | 3562020092475 |
12 | 129837a297789 |
13 | 61a674b5c6c1 |
14 | 2a07208cbb97 |
15 | 1412d69266d0 |
hex | a01a7988499 |
11002223035545 has 32 divisors (see below), whose sum is σ = 20119040613120. Its totient is φ = 5029415193600.
The previous prime is 11002223035541. The next prime is 11002223035547. The reversal of 11002223035545 is 54553032220011.
It is not a de Polignac number, because 11002223035545 - 22 = 11002223035541 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11002223035541) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1305141 + ... + 4869069.
It is an arithmetic number, because the mean of its divisors is an integer number (628720019160).
Almost surely, 211002223035545 is an apocalyptic number.
11002223035545 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11002223035545 is a deficient number, since it is larger than the sum of its proper divisors (9116817577575).
11002223035545 is a wasteful number, since it uses less digits than its factorization.
11002223035545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3593345.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 11002223035545 its reverse (54553032220011), we get a palindrome (65555255255556).
The spelling of 11002223035545 in words is "eleven trillion, two billion, two hundred twenty-three million, thirty-five thousand, five hundred forty-five".
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