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11002252213141 = 79371677428299
BaseRepresentation
bin1010000000011010100101…
…0101011011101110010101
31102221210201212120221220221
42200012221111123232111
52420230103031310031
635222210452154341
72213613031525360
oct240065125335625
942853655527827
1011002252213141
113562035600a92
1212983880089b1
1361a67ac07257
142a07247250d7
151412d928ba11
hexa01a955bb95

11002252213141 has 8 divisors (see below), whose sum is σ = 12587421963200. Its totient is φ = 9420437321568.

The previous prime is 11002252213109. The next prime is 11002252213163. The reversal of 11002252213141 is 14131225220011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11002252213141 - 25 = 11002252213109 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11002252813141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 838707591 + ... + 838720708.

It is an arithmetic number, because the mean of its divisors is an integer number (1573427745400).

Almost surely, 211002252213141 is an apocalyptic number.

It is an amenable number.

11002252213141 is a deficient number, since it is larger than the sum of its proper divisors (1585169750059).

11002252213141 is an equidigital number, since it uses as much as digits as its factorization.

11002252213141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1677429243.

The product of its (nonzero) digits is 960, while the sum is 25.

Adding to 11002252213141 its reverse (14131225220011), we get a palindrome (25133477433152).

The spelling of 11002252213141 in words is "eleven trillion, two billion, two hundred fifty-two million, two hundred thirteen thousand, one hundred forty-one".

Divisors: 1 7 937 6559 1677428299 11741998093 1571750316163 11002252213141