Base | Representation |
---|---|
bin | 10100011111100100… |
… | …11100011110010001 |
3 | 1001101202202202122220 |
4 | 22033302130132101 |
5 | 140013042102210 |
6 | 5015425251253 |
7 | 536435003163 |
oct | 121762343621 |
9 | 31352682586 |
10 | 11002300305 |
11 | 473656a077 |
12 | 2170793b29 |
13 | 1064551689 |
14 | 76530c933 |
15 | 445d95c70 |
hex | 28fc9c791 |
11002300305 has 16 divisors (see below), whose sum is σ = 17815775040. Its totient is φ = 5797195328.
The previous prime is 11002300301. The next prime is 11002300313. The reversal of 11002300305 is 50300320011.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 11002300305 - 22 = 11002300301 is a prime.
It is a super-2 number, since 2×110023003052 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is not an unprimeable number, because it can be changed into a prime (11002300301) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4417350 + ... + 4419839.
It is an arithmetic number, because the mean of its divisors is an integer number (1113485940).
Almost surely, 211002300305 is an apocalyptic number.
11002300305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11002300305 is a deficient number, since it is larger than the sum of its proper divisors (6813474735).
11002300305 is an equidigital number, since it uses as much as digits as its factorization.
11002300305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8837280.
The product of its (nonzero) digits is 90, while the sum is 15.
Adding to 11002300305 its reverse (50300320011), we get a palindrome (61302620316).
The spelling of 11002300305 in words is "eleven billion, two million, three hundred thousand, three hundred five".
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