11002302003113 has 4 divisors (see below), whose sum is σ = 11002768878720. Its totient is φ = 11001835127508.

The previous prime is 11002302003067. The next prime is 11002302003137. The reversal of 11002302003113 is 31130020320011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11002302003113 - 2²² = 11002297808809 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11002302003091 and 11002302003100.

It is not an unprimeable number, because it can be changed into a prime (11002307003113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233402453 + ... + 233449586.

It is an arithmetic number, because the mean of its divisors is an integer number (2750692219680).

Almost surely, 2^{11002302003113} is an apocalyptic number.

It is an amenable number.

11002302003113 is a deficient number, since it is larger than the sum of its proper divisors (466875607).

11002302003113 is an equidigital number, since it uses as much as digits as its factorization.

11002302003113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 466875606.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 11002302003113 its reverse (31130020320011), we get a palindrome (42132322323124).

The spelling of 11002302003113 in words is "eleven trillion, two billion, three hundred two million, three thousand, one hundred thirteen".