110030120113 has 4 divisors (see below), whose sum is σ = 110418919408. Its totient is φ = 109641320820.

The previous prime is 110030120099. The next prime is 110030120171. The reversal of 110030120113 is 311021030011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311021030011 = 52147 ⋅5964313.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110030120113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110030120093 and 110030120102.

It is not an unprimeable number, because it can be changed into a prime (110030120713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 194399223 + ... + 194399788.

It is an arithmetic number, because the mean of its divisors is an integer number (27604729852).

Almost surely, 2^110030120113 is an apocalyptic number.

It is an amenable number.

110030120113 is a deficient number, since it is larger than the sum of its proper divisors (388799295).

110030120113 is an equidigital number, since it uses as much as digits as its factorization.

110030120113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 388799294.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 110030120113 its reverse (311021030011), we get a palindrome (421051150124).

The spelling of 110030120113 in words is "one hundred ten billion, thirty million, one hundred twenty thousand, one hundred thirteen".