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110031331997 is a prime number
BaseRepresentation
bin110011001111001100…
…0001110001010011101
3101112000021100210210102
41212132120032022131
53300321010110442
6122314145150445
710643451614246
oct1463630161235
9345007323712
10110031331997
1142733900324
12193a932b425
13a4b6b4a252
14547b41bccd
152cdec36232
hex199e60e29d

110031331997 has 2 divisors, whose sum is σ = 110031331998. Its totient is φ = 110031331996.

The previous prime is 110031331979. The next prime is 110031332071. The reversal of 110031331997 is 799133130011.

Together with previous prime (110031331979) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109633169881 + 398162116 = 331109^2 + 19954^2 .

It is a cyclic number.

It is not a de Polignac number, because 110031331997 - 218 = 110031069853 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 110031331997.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110031331937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55015665998 + 55015665999.

It is an arithmetic number, because the mean of its divisors is an integer number (55015665999).

Almost surely, 2110031331997 is an apocalyptic number.

It is an amenable number.

110031331997 is a deficient number, since it is larger than the sum of its proper divisors (1).

110031331997 is an equidigital number, since it uses as much as digits as its factorization.

110031331997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15309, while the sum is 38.

The spelling of 110031331997 in words is "one hundred ten billion, thirty-one million, three hundred thirty-one thousand, nine hundred ninety-seven".