11003201221981 has 2 divisors, whose sum is σ = 11003201221982. Its totient is φ = 11003201221980.

The previous prime is 11003201221927. The next prime is 11003201222047. The reversal of 11003201221981 is 18912210230011.

11003201221981 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10968880324900 + 34320897081 = 3311930^2 + 185259^2 .

It is a cyclic number.

It is not a de Polignac number, because 11003201221981 - 2¹⁵ = 11003201189213 is a prime.

It is a super-2 number, since 2×11003201221981² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11003201251981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501600610990 + 5501600610991.

It is an arithmetic number, because the mean of its divisors is an integer number (5501600610991).

Almost surely, 2^{11003201221981} is an apocalyptic number.

It is an amenable number.

11003201221981 is a deficient number, since it is larger than the sum of its proper divisors (1).

11003201221981 is an equidigital number, since it uses as much as digits as its factorization.

11003201221981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 31.

Adding to 11003201221981 its reverse (18912210230011), we get a palindrome (29915411451992).

The spelling of 11003201221981 in words is "eleven trillion, three billion, two hundred one million, two hundred twenty-one thousand, nine hundred eighty-one".