Base | Representation |
---|---|
bin | 1010000000011110000111… |
… | …1101011001000100000101 |
3 | 1102221220012002011220111121 |
4 | 2200013201331121010011 |
5 | 2420234024231241401 |
6 | 35222445030033541 |
7 | 2213645415425551 |
oct | 240074175310405 |
9 | 42856162156447 |
10 | 11003202212101 |
11 | 35624828832a0 |
12 | 12985b21a88b1 |
13 | 61a79c988708 |
14 | 2a07b4978861 |
15 | 141342892ca1 |
hex | a01e1f59105 |
11003202212101 has 16 divisors (see below), whose sum is σ = 12304866974400. Its totient is φ = 9752107881600.
The previous prime is 11003202212083. The next prime is 11003202212131. The reversal of 11003202212101 is 10121220230011.
It is a cyclic number.
It is not a de Polignac number, because 11003202212101 - 211 = 11003202210053 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11003202212131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7892031 + ... + 9180988.
It is an arithmetic number, because the mean of its divisors is an integer number (769054185900).
Almost surely, 211003202212101 is an apocalyptic number.
11003202212101 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
11003202212101 is a deficient number, since it is larger than the sum of its proper divisors (1301664762299).
11003202212101 is a wasteful number, since it uses less digits than its factorization.
11003202212101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17074500.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 11003202212101 its reverse (10121220230011), we get a palindrome (21124422442112).
The spelling of 11003202212101 in words is "eleven trillion, three billion, two hundred two million, two hundred twelve thousand, one hundred one".
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