Base | Representation |
---|---|
bin | 10000000000110000010… |
… | …111001000111011000011 |
3 | 10220012010101211212102211 |
4 | 100000300113020323003 |
5 | 121011430142000003 |
6 | 2201251552322551 |
7 | 142332013116343 |
oct | 20006027107303 |
9 | 3805111755384 |
10 | 1100323000003 |
11 | 39470a714747 |
12 | 1592bbb43457 |
13 | 7c9b5999b36 |
14 | 3b382346d23 |
15 | 1d94e00496d |
hex | 100305c8ec3 |
1100323000003 has 4 divisors (see below), whose sum is σ = 1102135723840. Its totient is φ = 1098510276168.
The previous prime is 1100322999949. The next prime is 1100323000043. The reversal of 1100323000003 is 3000003230011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100323000003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1100323000043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 906361008 + ... + 906362221.
It is an arithmetic number, because the mean of its divisors is an integer number (275533930960).
Almost surely, 21100323000003 is an apocalyptic number.
1100323000003 is a deficient number, since it is larger than the sum of its proper divisors (1812723837).
1100323000003 is an equidigital number, since it uses as much as digits as its factorization.
1100323000003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1812723836.
The product of its (nonzero) digits is 54, while the sum is 13.
Adding to 1100323000003 its reverse (3000003230011), we get a palindrome (4100326230014).
The spelling of 1100323000003 in words is "one trillion, one hundred billion, three hundred twenty-three million, three", and thus it is an aban number.
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