Base | Representation |
---|---|
bin | 1010000000011110001111… |
… | …1000001011100010010001 |
3 | 1102221220021022202020112212 |
4 | 2200013203320023202101 |
5 | 2420234111001303101 |
6 | 35222452140001505 |
7 | 2213646256140155 |
oct | 240074370134221 |
9 | 42856238666485 |
10 | 11003234400401 |
11 | 3562499a688a1 |
12 | 1298600b30295 |
13 | 61a7a6548749 |
14 | 2a07b8d57065 |
15 | 1413456001bb |
hex | a01e3e0b891 |
11003234400401 has 2 divisors, whose sum is σ = 11003234400402. Its totient is φ = 11003234400400.
The previous prime is 11003234400373. The next prime is 11003234400407. The reversal of 11003234400401 is 10400443230011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10504729210000 + 498505190401 = 3241100^2 + 706049^2 .
It is an emirp because it is prime and its reverse (10400443230011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11003234400401 - 26 = 11003234400337 is a prime.
It is not a weakly prime, because it can be changed into another prime (11003234400407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501617200200 + 5501617200201.
It is an arithmetic number, because the mean of its divisors is an integer number (5501617200201).
Almost surely, 211003234400401 is an apocalyptic number.
It is an amenable number.
11003234400401 is a deficient number, since it is larger than the sum of its proper divisors (1).
11003234400401 is an equidigital number, since it uses as much as digits as its factorization.
11003234400401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 11003234400401 its reverse (10400443230011), we get a palindrome (21403677630412).
The spelling of 11003234400401 in words is "eleven trillion, three billion, two hundred thirty-four million, four hundred thousand, four hundred one".
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