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11003302113 = 33667767371
BaseRepresentation
bin10100011111101100…
…10001000011100001
31001101211122122212220
422033312101003201
5140013321131423
65015502541253
7536446344666
oct121766210341
931354578786
1011003302113
114737093811
122170b97829
13106481266b
147654cda6d
15445ee29e3
hex28fd910e1

11003302113 has 4 divisors (see below), whose sum is σ = 14671069488. Its totient is φ = 7335534740.

The previous prime is 11003302111. The next prime is 11003302127. The reversal of 11003302113 is 31120330011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11003302113 - 21 = 11003302111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11003302092 and 11003302101.

It is not an unprimeable number, because it can be changed into a prime (11003302111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1833883683 + ... + 1833883688.

It is an arithmetic number, because the mean of its divisors is an integer number (3667767372).

Almost surely, 211003302113 is an apocalyptic number.

It is an amenable number.

11003302113 is a deficient number, since it is larger than the sum of its proper divisors (3667767375).

11003302113 is an equidigital number, since it uses as much as digits as its factorization.

11003302113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3667767374.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11003302113 its reverse (31120330011), we get a palindrome (42123632124).

The spelling of 11003302113 in words is "eleven billion, three million, three hundred two thousand, one hundred thirteen".

Divisors: 1 3 3667767371 11003302113