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140013321131423 = 261753501460119
BaseRepresentation
bin11111110101011101100100…
…010001010001010110011111
3200100202010212002022010120002
4133311131210101101112133
5121322434240202201143
61213441122021044515
741330425423033655
oct3765354421212637
9610663762263502
10140013321131423
1140681352703473
1213853629b5673b
13601827949b59c
14268097656add5
15112c103c235b8
hex7f576445159f

140013321131423 has 4 divisors (see below), whose sum is σ = 140066822594160. Its totient is φ = 139959819668688.

The previous prime is 140013321131417. The next prime is 140013321131443. The reversal of 140013321131423 is 324131123310041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140013321131423 - 210 = 140013321130399 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140013321131443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26750727443 + ... + 26750732676.

It is an arithmetic number, because the mean of its divisors is an integer number (35016705648540).

Almost surely, 2140013321131423 is an apocalyptic number.

140013321131423 is a deficient number, since it is larger than the sum of its proper divisors (53501462737).

140013321131423 is an equidigital number, since it uses as much as digits as its factorization.

140013321131423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53501462736.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 140013321131423 its reverse (324131123310041), we get a palindrome (464144444441464).

The spelling of 140013321131423 in words is "one hundred forty trillion, thirteen billion, three hundred twenty-one million, one hundred thirty-one thousand, four hundred twenty-three".

Divisors: 1 2617 53501460119 140013321131423