Base | Representation |
---|---|
bin | 1010000000011110011111… |
… | …1111000011101100000101 |
3 | 1102221220110010102022200020 |
4 | 2200013213333003230011 |
5 | 2420234231121442013 |
6 | 35222503041005353 |
7 | 2213651053652046 |
oct | 240074777035405 |
9 | 42856403368606 |
10 | 11003303312133 |
11 | 3562524956240 |
12 | 1298620023859 |
13 | 61a7b78c5b12 |
14 | 2a07c41748cd |
15 | 14134b6b3623 |
hex | a01e7fc3b05 |
11003303312133 has 16 divisors (see below), whose sum is σ = 16005496774656. Its totient is φ = 6668380358640.
The previous prime is 11003303312101. The next prime is 11003303312161. The reversal of 11003303312133 is 33121330330011.
11003303312133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11003303312133 - 25 = 11003303312101 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11003303312173) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6431791 + ... + 7960812.
It is an arithmetic number, because the mean of its divisors is an integer number (1000343548416).
Almost surely, 211003303312133 is an apocalyptic number.
It is an amenable number.
11003303312133 is a deficient number, since it is larger than the sum of its proper divisors (5002193462523).
11003303312133 is a wasteful number, since it uses less digits than its factorization.
11003303312133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14415784.
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 11003303312133 its reverse (33121330330011), we get a palindrome (44124633642144).
The spelling of 11003303312133 in words is "eleven trillion, three billion, three hundred three million, three hundred twelve thousand, one hundred thirty-three".
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