Base | Representation |
---|---|
bin | 10000000000110000110… |
… | …101110001011100101111 |
3 | 10220012010221221211221221 |
4 | 100000300311301130233 |
5 | 121011434220432234 |
6 | 2201252440404211 |
7 | 142332141303343 |
oct | 20006065613457 |
9 | 3805127854857 |
10 | 1100331030319 |
11 | 3947141a9a74 |
12 | 159302776667 |
13 | 7c9b754bcc1 |
14 | 3b383437623 |
15 | 1d94ea8deb4 |
hex | 10030d7172f |
1100331030319 has 2 divisors, whose sum is σ = 1100331030320. Its totient is φ = 1100331030318.
The previous prime is 1100331030289. The next prime is 1100331030373. The reversal of 1100331030319 is 9130301330011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100331030319 - 25 = 1100331030287 is a prime.
It is a super-2 number, since 2×11003310303192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1100331030293 and 1100331030302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100331030119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550165515159 + 550165515160.
It is an arithmetic number, because the mean of its divisors is an integer number (550165515160).
Almost surely, 21100331030319 is an apocalyptic number.
1100331030319 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100331030319 is an equidigital number, since it uses as much as digits as its factorization.
1100331030319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 729, while the sum is 25.
The spelling of 1100331030319 in words is "one trillion, one hundred billion, three hundred thirty-one million, thirty thousand, three hundred nineteen".
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