Search a number
-
+
110033123020 = 2255501656151
BaseRepresentation
bin110011001111001111…
…1000011011011001100
3101112000101201210121121
41212132133003123030
53300321434414040
6122314251410324
710643503054012
oct1463637033314
9345011653547
10110033123020
1142734913a07
12193a9a539a4
13a4b7326522
14547b7668b2
152cdee8bc4a
hex199e7c36cc

110033123020 has 12 divisors (see below), whose sum is σ = 231069558384. Its totient is φ = 44013249200.

The previous prime is 110033123003. The next prime is 110033123041. The reversal of 110033123020 is 20321330011.

It is a junction number, because it is equal to n+sod(n) for n = 110033122985 and 110033123003.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2750828056 + ... + 2750828095.

It is an arithmetic number, because the mean of its divisors is an integer number (19255796532).

Almost surely, 2110033123020 is an apocalyptic number.

110033123020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

110033123020 is an abundant number, since it is smaller than the sum of its proper divisors (121036435364).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110033123020 is a wasteful number, since it uses less digits than its factorization.

110033123020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5501656160 (or 5501656158 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 110033123020 its reverse (20321330011), we get a palindrome (130354453031).

The spelling of 110033123020 in words is "one hundred ten billion, thirty-three million, one hundred twenty-three thousand, twenty".

Divisors: 1 2 4 5 10 20 5501656151 11003312302 22006624604 27508280755 55016561510 110033123020