Base | Representation |
---|---|
bin | 11001000001001100100000… |
… | …100010010110101111111101 |
3 | 112102121002012202220012200000 |
4 | 121001030200202112233331 |
5 | 103410241211114030323 |
6 | 1030004334533424513 |
7 | 32114434033602423 |
oct | 3101144042265775 |
9 | 472532182805600 |
10 | 110033313033213 |
11 | 320729587100a9 |
12 | 10411239a9b139 |
13 | 4952134b5cc2b |
14 | 1d258d8399113 |
15 | cac344115e43 |
hex | 641320896bfd |
110033313033213 has 24 divisors (see below), whose sum is σ = 164827183929408. Its totient is φ = 73353930757344.
The previous prime is 110033313033199. The next prime is 110033313033227. The reversal of 110033313033213 is 312330313330011.
110033313033213 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 3 + 3 + 31 + 303 + 321 + 3 = 666.
It is an interprime number because it is at equal distance from previous prime (110033313033199) and next prime (110033313033227).
It is not a de Polignac number, because 110033313033213 - 28 = 110033313032957 is a prime.
It is a super-2 number, since 2×1100333130332132 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110033313033113) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6163920 + ... + 16064262.
It is an arithmetic number, because the mean of its divisors is an integer number (6867799330392).
Almost surely, 2110033313033213 is an apocalyptic number.
It is an amenable number.
110033313033213 is a deficient number, since it is larger than the sum of its proper divisors (54793870896195).
110033313033213 is an frugal number, since it uses more digits than its factorization.
110033313033213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9946095 (or 9946083 counting only the distinct ones).
The product of its (nonzero) digits is 4374, while the sum is 27.
Adding to 110033313033213 its reverse (312330313330011), we get a palindrome (422363626363224).
The spelling of 110033313033213 in words is "one hundred ten trillion, thirty-three billion, three hundred thirteen million, thirty-three thousand, two hundred thirteen".
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