Base | Representation |
---|---|
bin | 11001000001001101111010… |
… | …010111111000110111010111 |
3 | 112102121020002210222012001102 |
4 | 121001031322113320313113 |
5 | 103410302302440120212 |
6 | 1030005144254220315 |
7 | 32114516264621012 |
oct | 3101157227706727 |
9 | 472536083865042 |
10 | 110034820238807 |
11 | 32073561471a62 |
12 | 1041159a7b469b |
13 | 49523151a5b69 |
14 | 1d259dc616379 |
15 | cac3d15d55c2 |
hex | 64137a5f8dd7 |
110034820238807 has 4 divisors (see below), whose sum is σ = 110035202085120. Its totient is φ = 110034438392496.
The previous prime is 110034820238767. The next prime is 110034820238887. The reversal of 110034820238807 is 708832028430011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 110034820238807 - 236 = 109966100762071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110034820238887) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190490582 + ... + 191067347.
It is an arithmetic number, because the mean of its divisors is an integer number (27508800521280).
Almost surely, 2110034820238807 is an apocalyptic number.
110034820238807 is a deficient number, since it is larger than the sum of its proper divisors (381846313).
110034820238807 is an equidigital number, since it uses as much as digits as its factorization.
110034820238807 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 381846312.
The product of its (nonzero) digits is 516096, while the sum is 47.
Adding to 110034820238807 its reverse (708832028430011), we get a palindrome (818866848668818).
The spelling of 110034820238807 in words is "one hundred ten trillion, thirty-four billion, eight hundred twenty million, two hundred thirty-eight thousand, eight hundred seven".
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