1100389931 has 2 divisors, whose sum is σ = 1100389932. Its totient is φ = 1100389930.

The previous prime is 1100389903. The next prime is 1100389933. The reversal of 1100389931 is 1399830011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100389931 is a prime.

It is a super-2 number, since 2×1100389931² = 2421716000492369522, which contains 22 as substring.

Together with 1100389933, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100389891 and 1100389900.

It is not a weakly prime, because it can be changed into another prime (1100389933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550194965 + 550194966.

It is an arithmetic number, because the mean of its divisors is an integer number (550194966).

Almost surely, 2^1100389931 is an apocalyptic number.

1100389931 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100389931 is an equidigital number, since it uses as much as digits as its factorization.

1100389931 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5832, while the sum is 35.

The square root of 1100389931 is about 33172.1258137009. The cubic root of 1100389931 is about 1032.4020762034.

The spelling of 1100389931 in words is "one billion, one hundred million, three hundred eighty-nine thousand, nine hundred thirty-one".