11004011140081 has 2 divisors, whose sum is σ = 11004011140082. Its totient is φ = 11004011140080.

The previous prime is 11004011139977. The next prime is 11004011140183. The reversal of 11004011140081 is 18004111040011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6745401090481 + 4258610049600 = 2597191^2 + 2063640^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11004011140081 is a prime.

It is a super-2 number, since 2×11004011140081² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11004011147081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502005570040 + 5502005570041.

It is an arithmetic number, because the mean of its divisors is an integer number (5502005570041).

Almost surely, 2^{11004011140081} is an apocalyptic number.

It is an amenable number.

11004011140081 is a deficient number, since it is larger than the sum of its proper divisors (1).

11004011140081 is an equidigital number, since it uses as much as digits as its factorization.

11004011140081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 22.

Adding to 11004011140081 its reverse (18004111040011), we get a palindrome (29008122180092).

The spelling of 11004011140081 in words is "eleven trillion, four billion, eleven million, one hundred forty thousand, eighty-one".