11004011140183 has 2 divisors, whose sum is σ = 11004011140184. Its totient is φ = 11004011140182.

The previous prime is 11004011140081. The next prime is 11004011140219. The reversal of 11004011140183 is 38104111040011.

It is a strong prime.

It is an emirp because it is prime and its reverse (38104111040011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11004011140183 - 2²¹ = 11004009043031 is a prime.

It is a super-2 number, since 2×11004011140183² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11004011141183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502005570091 + 5502005570092.

It is an arithmetic number, because the mean of its divisors is an integer number (5502005570092).

Almost surely, 2^{11004011140183} is an apocalyptic number.

11004011140183 is a deficient number, since it is larger than the sum of its proper divisors (1).

11004011140183 is an equidigital number, since it uses as much as digits as its factorization.

11004011140183 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 25.

Adding to 11004011140183 its reverse (38104111040011), we get a palindrome (49108122180194).

The spelling of 11004011140183 in words is "eleven trillion, four billion, eleven million, one hundred forty thousand, one hundred eighty-three".