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110040113 = 473836113
BaseRepresentation
bin1101000111100…
…01010000110001
321200001121122202
412203301100301
5211132240423
614530312545
72504216441
oct643612061
9250047582
10110040113
1157129847
1230a28755
1319a4a6c1
1410886121
1599d9728
hex68f1431

110040113 has 8 divisors (see below), whose sum is σ = 112693248. Its totient is φ = 107400064.

The previous prime is 110040107. The next prime is 110040121. The reversal of 110040113 is 311040011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 110040113 - 28 = 110039857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110040094 and 110040103.

It is not an unprimeable number, because it can be changed into a prime (110040103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14945 + ... + 21057.

It is an arithmetic number, because the mean of its divisors is an integer number (14086656).

Almost surely, 2110040113 is an apocalyptic number.

It is an amenable number.

110040113 is a deficient number, since it is larger than the sum of its proper divisors (2653135).

110040113 is an equidigital number, since it uses as much as digits as its factorization.

110040113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6543.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 110040113 is about 10490.0006196377. Note that the first 3 decimals coincide. The cubic root of 110040113 is about 479.2002205144.

Adding to 110040113 its reverse (311040011), we get a palindrome (421080124).

The spelling of 110040113 in words is "one hundred ten million, forty thousand, one hundred thirteen".

Divisors: 1 47 383 6113 18001 287311 2341279 110040113