11004013531 has 4 divisors (see below), whose sum is σ = 12576015472. Its totient is φ = 9432011592.

The previous prime is 11004013507. The next prime is 11004013561. The reversal of 11004013531 is 13531040011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11004013531 - 2¹⁷ = 11003882459 is a prime.

It is a super-2 number, since 2×11004013531² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11004013499 and 11004013508.

It is not an unprimeable number, because it can be changed into a prime (11004013561) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 786000960 + ... + 786000973.

It is an arithmetic number, because the mean of its divisors is an integer number (3144003868).

Almost surely, 2^11004013531 is an apocalyptic number.

11004013531 is a deficient number, since it is larger than the sum of its proper divisors (1572001941).

11004013531 is an equidigital number, since it uses as much as digits as its factorization.

11004013531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1572001940.

The product of its (nonzero) digits is 180, while the sum is 19.

Adding to 11004013531 its reverse (13531040011), we get a palindrome (24535053542).

The spelling of 11004013531 in words is "eleven billion, four million, thirteen thousand, five hundred thirty-one".