Search a number
-
+
1100402131547 is a prime number
BaseRepresentation
bin10000000000110101000…
…101000000001001011011
310220012022220202011111202
4100000311011000021123
5121012110421202142
62201303500344415
7142333663534505
oct20006505001133
93805286664452
101100402131547
11394750352414
1215932254510b
137c9c91b4b34
143b38ca64d75
151d955e36032
hex1003514025b

1100402131547 has 2 divisors, whose sum is σ = 1100402131548. Its totient is φ = 1100402131546.

The previous prime is 1100402131489. The next prime is 1100402131561. The reversal of 1100402131547 is 7451312040011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1100402131547 - 220 = 1100401082971 is a prime.

It is a super-2 number, since 2×11004021315472 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1100402137547) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550201065773 + 550201065774.

It is an arithmetic number, because the mean of its divisors is an integer number (550201065774).

Almost surely, 21100402131547 is an apocalyptic number.

1100402131547 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100402131547 is an equidigital number, since it uses as much as digits as its factorization.

1100402131547 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3360, while the sum is 29.

Adding to 1100402131547 its reverse (7451312040011), we get a palindrome (8551714171558).

The spelling of 1100402131547 in words is "one trillion, one hundred billion, four hundred two million, one hundred thirty-one thousand, five hundred forty-seven".