Base | Representation |
---|---|
bin | 1010000000100001001101… |
… | …0100010101110000010011 |
3 | 1102221222022210101201020121 |
4 | 2200020103110111300103 |
5 | 2420242223224431233 |
6 | 35223103131051111 |
7 | 2214005062233421 |
oct | 240102324256023 |
9 | 42858283351217 |
10 | 11004030311443 |
11 | 3562868266614 |
12 | 12987a35a0a97 |
13 | 61a8a23c9420 |
14 | 2a085293a111 |
15 | 14139041a92d |
hex | a0213515c13 |
11004030311443 has 16 divisors (see below), whose sum is σ = 11968494199200. Its totient is φ = 10056568193280.
The previous prime is 11004030311371. The next prime is 11004030311563. The reversal of 11004030311443 is 34411303040011.
It is a happy number.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11004030311443 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11004030311243) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1185793 + ... + 4838818.
It is an arithmetic number, because the mean of its divisors is an integer number (748030887450).
Almost surely, 211004030311443 is an apocalyptic number.
11004030311443 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11004030311443 is a deficient number, since it is larger than the sum of its proper divisors (964463887757).
11004030311443 is a wasteful number, since it uses less digits than its factorization.
11004030311443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6026022.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11004030311443 its reverse (34411303040011), we get a palindrome (45415333351454).
The spelling of 11004030311443 in words is "eleven trillion, four billion, thirty million, three hundred eleven thousand, four hundred forty-three".
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