11004032011 has 4 divisors (see below), whose sum is σ = 12576036592. Its totient is φ = 9432027432.

The previous prime is 11004031873. The next prime is 11004032021. The reversal of 11004032011 is 11023040011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11023040011 = 53 ⋅207981887.

It is a cyclic number.

It is not a de Polignac number, because 11004032011 - 2¹³ = 11004023819 is a prime.

It is a super-2 number, since 2×11004032011² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11004031982 and 11004032000.

It is not an unprimeable number, because it can be changed into a prime (11004032021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 786002280 + ... + 786002293.

It is an arithmetic number, because the mean of its divisors is an integer number (3144009148).

Almost surely, 2^11004032011 is an apocalyptic number.

11004032011 is a deficient number, since it is larger than the sum of its proper divisors (1572004581).

11004032011 is an equidigital number, since it uses as much as digits as its factorization.

11004032011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1572004580.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 11004032011 its reverse (11023040011), we get a palindrome (22027072022).

The spelling of 11004032011 in words is "eleven billion, four million, thirty-two thousand, eleven".