Base | Representation |
---|---|
bin | 11001000001010011000010… |
… | …110010011011010011001011 |
3 | 112102121202022210210021110201 |
4 | 121001103002302123103023 |
5 | 103410400044002404233 |
6 | 1030011455122153031 |
7 | 32115102651065500 |
oct | 3101230262332313 |
9 | 472552283707421 |
10 | 110040330122443 |
11 | 320759296770a6 |
12 | 10412677ab2777 |
13 | 49529b286a436 |
14 | 1d25da22c34a7 |
15 | cac6051a877d |
hex | 6414c2c9b4cb |
110040330122443 has 12 divisors (see below), whose sum is σ = 128179313636520. Its totient is φ = 94192650613152.
The previous prime is 110040330122381. The next prime is 110040330122449. The reversal of 110040330122443 is 344221033040011.
It is a happy number.
It is a de Polignac number, because none of the positive numbers 2k-110040330122443 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (110040330122449) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1519396146 + ... + 1519468567.
It is an arithmetic number, because the mean of its divisors is an integer number (10681609469710).
Almost surely, 2110040330122443 is an apocalyptic number.
110040330122443 is a deficient number, since it is larger than the sum of its proper divisors (18138983514077).
110040330122443 is an equidigital number, since it uses as much as digits as its factorization.
110040330122443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3038865466 (or 3038865459 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 110040330122443 its reverse (344221033040011), we get a palindrome (454261363162454).
The spelling of 110040330122443 in words is "one hundred ten trillion, forty billion, three hundred thirty million, one hundred twenty-two thousand, four hundred forty-three".
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