Base | Representation |
---|---|
bin | 110011001111011111… |
… | …0000010011100110101 |
3 | 101112000222000110112221 |
4 | 1212132332002130311 |
5 | 3300331024323433 |
6 | 122315141442341 |
7 | 10643632103464 |
oct | 1463676023465 |
9 | 345028013487 |
10 | 110041245493 |
11 | 427394614a3 |
12 | 193b07103b1 |
13 | a4b8c0b61a |
14 | 547c87c9db |
15 | 2ce0a4372d |
hex | 199ef82735 |
110041245493 has 2 divisors, whose sum is σ = 110041245494. Its totient is φ = 110041245492.
The previous prime is 110041245469. The next prime is 110041245533. The reversal of 110041245493 is 394542140011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 89803906929 + 20237338564 = 299673^2 + 142258^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110041245493 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110041245893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55020622746 + 55020622747.
It is an arithmetic number, because the mean of its divisors is an integer number (55020622747).
Almost surely, 2110041245493 is an apocalyptic number.
It is an amenable number.
110041245493 is a deficient number, since it is larger than the sum of its proper divisors (1).
110041245493 is an equidigital number, since it uses as much as digits as its factorization.
110041245493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 34.
The spelling of 110041245493 in words is "one hundred ten billion, forty-one million, two hundred forty-five thousand, four hundred ninety-three".
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