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11004155234 = 25502077617
BaseRepresentation
bin10100011111110011…
…00001010101100010
31001101220021000010222
422033321201111202
5140014030431414
65015533123042
7536456530142
oct121771412542
931356230128
1011004155234
114737616776
122171329482
131064a50a77
14765672922
1544611068e
hex28fe61562

11004155234 has 4 divisors (see below), whose sum is σ = 16506232854. Its totient is φ = 5502077616.

The previous prime is 11004155231. The next prime is 11004155243. The reversal of 11004155234 is 43255140011.

11004155234 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43255140011 = 330713079873.

It can be written as a sum of positive squares in only one way, i.e., 10763440009 + 240715225 = 103747^2 + 15515^2 .

It is not an unprimeable number, because it can be changed into a prime (11004155231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2751038807 + ... + 2751038810.

Almost surely, 211004155234 is an apocalyptic number.

11004155234 is a deficient number, since it is larger than the sum of its proper divisors (5502077620).

11004155234 is an equidigital number, since it uses as much as digits as its factorization.

11004155234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5502077619.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 11004155234 its reverse (43255140011), we get a palindrome (54259295245).

The spelling of 11004155234 in words is "eleven billion, four million, one hundred fifty-five thousand, two hundred thirty-four".

Divisors: 1 2 5502077617 11004155234