Base | Representation |
---|---|
bin | 1010000000100001101100… |
… | …1111101111010101101001 |
3 | 1102221222200001200102010111 |
4 | 2200020123033233111221 |
5 | 2420243011302320431 |
6 | 35223124242014321 |
7 | 2214011265640054 |
oct | 240103317572551 |
9 | 42858601612114 |
10 | 11004163323241 |
11 | 3562926355320 |
12 | 12988200473a1 |
13 | 61a8c3b2aa2a |
14 | 2a0866481a9b |
15 | 14139be417b1 |
hex | a021b3ef569 |
11004163323241 has 4 divisors (see below), whose sum is σ = 12004541807184. Its totient is φ = 10003784839300.
The previous prime is 11004163323229. The next prime is 11004163323287. The reversal of 11004163323241 is 14232336140011.
11004163323241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11004163323241 is a prime.
It is a super-2 number, since 2×110041633232412 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11004563323241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500189241955 + ... + 500189241976.
It is an arithmetic number, because the mean of its divisors is an integer number (3001135451796).
Almost surely, 211004163323241 is an apocalyptic number.
11004163323241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
11004163323241 is a deficient number, since it is larger than the sum of its proper divisors (1000378483943).
11004163323241 is a wasteful number, since it uses less digits than its factorization.
11004163323241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1000378483942.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 11004163323241 its reverse (14232336140011), we get a palindrome (25236499463252).
The spelling of 11004163323241 in words is "eleven trillion, four billion, one hundred sixty-three million, three hundred twenty-three thousand, two hundred forty-one".
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