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110043115381 is a prime number
BaseRepresentation
bin110011001111100010…
…1001010111101110101
3101112001002112110120001
41212133011022331311
53300332014143011
6122315245511301
710643654022163
oct1463705127565
9345032473501
10110043115381
114273a519361
12193b1272531
13a4b9414774
14547cc08233
152ce0cb27c1
hex199f14af75

110043115381 has 2 divisors, whose sum is σ = 110043115382. Its totient is φ = 110043115380.

The previous prime is 110043115289. The next prime is 110043115387. The reversal of 110043115381 is 183511340011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 58498678225 + 51544437156 = 241865^2 + 227034^2 .

It is an emirp because it is prime and its reverse (183511340011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110043115381 - 221 = 110041018229 is a prime.

It is a super-2 number, since 2×1100431153812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110043115387) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55021557690 + 55021557691.

It is an arithmetic number, because the mean of its divisors is an integer number (55021557691).

Almost surely, 2110043115381 is an apocalyptic number.

It is an amenable number.

110043115381 is a deficient number, since it is larger than the sum of its proper divisors (1).

110043115381 is an equidigital number, since it uses as much as digits as its factorization.

110043115381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 28.

Adding to 110043115381 its reverse (183511340011), we get a palindrome (293554455392).

The spelling of 110043115381 in words is "one hundred ten billion, forty-three million, one hundred fifteen thousand, three hundred eighty-one".