1100445553 has 4 divisors (see below), whose sum is σ = 1158363760. Its totient is φ = 1042527348.

The previous prime is 1100445539. The next prime is 1100445559. The reversal of 1100445553 is 3555440011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3555440011 = 953 ⋅3730787.

It is a cyclic number.

It is not a de Polignac number, because 1100445553 - 2⁹ = 1100445041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1100445559) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28959075 + ... + 28959112.

It is an arithmetic number, because the mean of its divisors is an integer number (289590940).

Almost surely, 2^1100445553 is an apocalyptic number.

It is an amenable number.

1100445553 is a deficient number, since it is larger than the sum of its proper divisors (57918207).

1100445553 is an equidigital number, since it uses as much as digits as its factorization.

1100445553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57918206.

The product of its (nonzero) digits is 6000, while the sum is 28.

The square root of 1100445553 is about 33172.9641877237. The cubic root of 1100445553 is about 1032.4194710374.

Adding to 1100445553 its reverse (3555440011), we get a palindrome (4655885564).

The spelling of 1100445553 in words is "one billion, one hundred million, four hundred forty-five thousand, five hundred fifty-three".