11004748517 has 4 divisors (see below), whose sum is σ = 12576855456. Its totient is φ = 9432641580.

The previous prime is 11004748487. The next prime is 11004748543. The reversal of 11004748517 is 71584740011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 71584740011 = 37 ⋅1934722703.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11004748517 is a prime.

It is a super-3 number, since 3×11004748517³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11004742517) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 786053459 + ... + 786053472.

It is an arithmetic number, because the mean of its divisors is an integer number (3144213864).

Almost surely, 2^11004748517 is an apocalyptic number.

It is an amenable number.

11004748517 is a deficient number, since it is larger than the sum of its proper divisors (1572106939).

11004748517 is an equidigital number, since it uses as much as digits as its factorization.

11004748517 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1572106938.

The product of its (nonzero) digits is 31360, while the sum is 38.

The spelling of 11004748517 in words is "eleven billion, four million, seven hundred forty-eight thousand, five hundred seventeen".