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11004944369 is a prime number
BaseRepresentation
bin10100011111111001…
…00001111111110001
31001101221202002122012
422033330201333301
5140014231204434
65020002052305
7536466324626
oct121774417761
931357662565
1011004944369
114738005651
12217164a095
131064c69003
147657da34d
154462193ce
hex28ff21ff1

11004944369 has 2 divisors, whose sum is σ = 11004944370. Its totient is φ = 11004944368.

The previous prime is 11004944333. The next prime is 11004944371. The reversal of 11004944369 is 96344940011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7536323344 + 3468621025 = 86812^2 + 58895^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11004944369 is a prime.

It is a super-2 number, since 2×110049443692 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 11004944371, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (11004944569) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502472184 + 5502472185.

It is an arithmetic number, because the mean of its divisors is an integer number (5502472185).

Almost surely, 211004944369 is an apocalyptic number.

It is an amenable number.

11004944369 is a deficient number, since it is larger than the sum of its proper divisors (1).

11004944369 is an equidigital number, since it uses as much as digits as its factorization.

11004944369 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 41.

The spelling of 11004944369 in words is "eleven billion, four million, nine hundred forty-four thousand, three hundred sixty-nine".