110049969443 has 4 divisors (see below), whose sum is σ = 110686096608. Its totient is φ = 109413842280.

The previous prime is 110049969439. The next prime is 110049969473. The reversal of 110049969443 is 344969940011.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 110049969443 - 2² = 110049969439 is a prime.

It is a super-2 number, since 2×110049969443² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110049969391 and 110049969400.

It is not an unprimeable number, because it can be changed into a prime (110049969433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 318063323 + ... + 318063668.

It is an arithmetic number, because the mean of its divisors is an integer number (27671524152).

Almost surely, 2^110049969443 is an apocalyptic number.

110049969443 is a deficient number, since it is larger than the sum of its proper divisors (636127165).

110049969443 is an equidigital number, since it uses as much as digits as its factorization.

110049969443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 636127164.

The product of its (nonzero) digits is 839808, while the sum is 50.

The spelling of 110049969443 in words is "one hundred ten billion, forty-nine million, nine hundred sixty-nine thousand, four hundred forty-three".