11005001341 has 4 divisors (see below), whose sum is σ = 11007158812. Its totient is φ = 11002843872.

The previous prime is 11005001311. The next prime is 11005001351. The reversal of 11005001341 is 14310050011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 14310050011 = 641 ⋅22324571.

It can be written as a sum of positive squares in 2 ways, for example, as 2537136900 + 8467864441 = 50370^2 + 92021^2 .

It is a cyclic number.

It is not a de Polignac number, because 11005001341 - 2⁷ = 11005001213 is a prime.

It is a super-2 number, since 2×11005001341² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11005001311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1071066 + ... + 1081291.

It is an arithmetic number, because the mean of its divisors is an integer number (2751789703).

Almost surely, 2^11005001341 is an apocalyptic number.

It is an amenable number.

11005001341 is a deficient number, since it is larger than the sum of its proper divisors (2157471).

11005001341 is an equidigital number, since it uses as much as digits as its factorization.

11005001341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2157470.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 11005001341 its reverse (14310050011), we get a palindrome (25315051352).

The spelling of 11005001341 in words is "eleven billion, five million, one thousand, three hundred forty-one".