Base | Representation |
---|---|
bin | 10000000000111010111… |
… | …100101000010011110011 |
3 | 10220012120210000212220101 |
4 | 100000322330220103303 |
5 | 121012311123200201 |
6 | 2201321335053231 |
7 | 142336300520626 |
oct | 20007274502363 |
9 | 3805523025811 |
10 | 1100500600051 |
11 | 3947a0998246 |
12 | 15934b511217 |
13 | 7ca13710518 |
14 | 3b39bb77dbd |
15 | 1d95e8d6d01 |
hex | 1003af284f3 |
1100500600051 has 2 divisors, whose sum is σ = 1100500600052. Its totient is φ = 1100500600050.
The previous prime is 1100500600049. The next prime is 1100500600061. The reversal of 1100500600051 is 1500060050011.
It is a weak prime.
It is an emirp because it is prime and its reverse (1500060050011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1100500600051 - 21 = 1100500600049 is a prime.
It is a super-2 number, since 2×11005006000512 (a number of 25 digits) contains 22 as substring.
Together with 1100500600049, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1100500600061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550250300025 + 550250300026.
It is an arithmetic number, because the mean of its divisors is an integer number (550250300026).
Almost surely, 21100500600051 is an apocalyptic number.
1100500600051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100500600051 is an equidigital number, since it uses as much as digits as its factorization.
1100500600051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 150, while the sum is 19.
Adding to 1100500600051 its reverse (1500060050011), we get a palindrome (2600560650062).
The spelling of 1100500600051 in words is "one trillion, one hundred billion, five hundred million, six hundred thousand, fifty-one".
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