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1100500600051 is a prime number
BaseRepresentation
bin10000000000111010111…
…100101000010011110011
310220012120210000212220101
4100000322330220103303
5121012311123200201
62201321335053231
7142336300520626
oct20007274502363
93805523025811
101100500600051
113947a0998246
1215934b511217
137ca13710518
143b39bb77dbd
151d95e8d6d01
hex1003af284f3

1100500600051 has 2 divisors, whose sum is σ = 1100500600052. Its totient is φ = 1100500600050.

The previous prime is 1100500600049. The next prime is 1100500600061. The reversal of 1100500600051 is 1500060050011.

It is a weak prime.

It is an emirp because it is prime and its reverse (1500060050011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100500600051 - 21 = 1100500600049 is a prime.

It is a super-2 number, since 2×11005006000512 (a number of 25 digits) contains 22 as substring.

Together with 1100500600049, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1100500600061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550250300025 + 550250300026.

It is an arithmetic number, because the mean of its divisors is an integer number (550250300026).

Almost surely, 21100500600051 is an apocalyptic number.

1100500600051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100500600051 is an equidigital number, since it uses as much as digits as its factorization.

1100500600051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 150, while the sum is 19.

Adding to 1100500600051 its reverse (1500060050011), we get a palindrome (2600560650062).

The spelling of 1100500600051 in words is "one trillion, one hundred billion, five hundred million, six hundred thousand, fifty-one".