11005044013 has 2 divisors, whose sum is σ = 11005044014. Its totient is φ = 11005044012.

The previous prime is 11005043999. The next prime is 11005044019. The reversal of 11005044013 is 31044050011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10080762409 + 924281604 = 100403^2 + 30402^2 .

It is a cyclic number.

It is not a de Polignac number, because 11005044013 - 2⁵ = 11005043981 is a prime.

It is a super-2 number, since 2×11005044013² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11005044019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502522006 + 5502522007.

It is an arithmetic number, because the mean of its divisors is an integer number (5502522007).

Almost surely, 2^11005044013 is an apocalyptic number.

It is an amenable number.

11005044013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11005044013 is an equidigital number, since it uses as much as digits as its factorization.

11005044013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 11005044013 its reverse (31044050011), we get a palindrome (42049094024).

The spelling of 11005044013 in words is "eleven billion, five million, forty-four thousand, thirteen".